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Serious Serious
Reported By: Roy Lambert
Reported On: 5/23/2019
For: Version 2.31 Build 4
# 4746 Using an Escape Character with a LIKE Operator Fails if the Escaped Character is the Last Character

If you do use % as part of a text field then according to the manual you can escape the character with the LIKE operator, but it doesn't seem to work here on my ansi database.

select * from companies where _name LIKE '20/%' ESCAPE '/'



Comments Comments
The issue was when the escaped character was the last character in the pattern string.


Resolution Resolution
Fixed Problem on 5/25/2019 in version 2.31 build 5


Products Affected Products Affected
ElevateDB Additional Software and Utilities
ElevateDB DAC Client-Server
ElevateDB DAC Client-Server with Source
ElevateDB DAC Standard
ElevateDB DAC Standard with Source
ElevateDB DAC Trial
ElevateDB LCL Standard with Source
ElevateDB PHP Standard
ElevateDB PHP Standard with Source
ElevateDB PHP Trial
ElevateDB VCL Client-Server
ElevateDB VCL Client-Server with Source
ElevateDB VCL Standard
ElevateDB VCL Standard with Source
ElevateDB VCL Trial

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